Construct a triangle PQR in which QR = 6cm, `angleQ=60^@` and PR – PQ = 2cm.

Explanation

Draw base `QR` of length `6cm`. Lets draw `/_Q=60^@` Let the ray be `QX`.



Open the compass to length `PR-PQ=2cm`. From `Q` as center cut an arc on ray `QX`. Let the arc intersect `QX` at `D`. Join `RD`.



Draw perpendicular bisector of `RD`. Mark point `P` where perpendicular bisector intersects `RD`. Join `PR`



`/_\PQR` is the required triangle.