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Value of equilibrium constant (KP​) for ...

Value of equilibrium constant `(K_P​)` for a reaction A(g) 2B(g) is 0.0005 atm. What does it indicate ?
(I) Products are more stable than reactants.
(II) Reactants are very less dissociated.
(III) Reactants are more stable than products.
(IV) Value of `K_C​` will be less than `K_P`​ at 300 K.

A

II and III

B

III and IV

C

II, III and IV

D

I, II, III and IV

Text Solution

Verified by Experts

The correct Answer is:
C
Very small value of `K_P`​ indicates that reactants are more stable and very less dissociation.
Unit of `K_P`​ = atm indicates that `Deltan_g`​ = 1 and `K_P`​ is greater than `K_C`
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