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A metallic element exists as simple cubi...

A metallic element exists as simple cubic lattice. Each edge of the unit cell is 3Å. The density of the metal is `9 "g cm"^(–3)`. How many number of unit cells will be present in 100 g of the metal :-

A

6.85 × 102

B

4.12 × 1023

C

4.37 × 105

D

2.12 × 106

Text Solution

Verified by Experts

The correct Answer is:
B
`C.D.=(ZxxM_W)/(VxxN_A) = (ZxxM_0)/(VxxN_0)`
Number of unit cell present in 100 g of the metal `M_0/(V xx C.D.) = 100/((3xx10^(-8))^3) xx9`
= 4.12 × 1023
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