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100 ml Fe(OH)​(3) is coagulated by 10 ml...

100 ml `Fe(OH)_​(3)` is coagulated by 10 ml 1N `Na_​(2)​SO​_(4)`​. Then what will be coagulation value of `Na_(​2)​SO​_(4)`​?

A

5

B

10

C

50

D

100

Text Solution

Verified by Experts

The correct Answer is:
C
100 ml `Fe(OH)_3 ` is coagulated by =`10xx1/2`=5 milli mol
1 mol `Fe(OH)_3` is coagulated by = `5/100`
1000 ml `Fe(OH)_3` is coagulated by `=(1000xx5)/100`=50
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