[2(1+cot A+tan A)(sin A-cos A)=sin A tan A-cot A cos Ax],[sec theta+tan thetaquad (1+sin theta)^(2)]

((sec theta + tan theta) (1- sin theta))/(cosec theta (1 + cos theta)(cosec theta - cot theta)) is equal to: ((sec theta + tan theta) (1- sin theta))/(cosec theta (1 + cos theta)(cosec theta - cot theta)) बराबर है :

(sin theta" cosec "theta tan theta cot theta)/(sin^(2)theta+cos^(2)theta)

cos ect theta(sec theta-1)-cot theta(1-cos theta)=tan theta-sin theta

(tan A) / (1-cot A) + (cot A) / (1-tan A) = 1 + tan A + cot A = 1 + sec A cos ecA (1 + cos theta + sin theta) / (1 + cos theta-sin theta) = (1 + sin theta) / (cos theta)

cos ec theta(sec theta-1)-cot theta(1-cos theta)=tan theta-sin theta

Prove that (sin theta- "cosec" theta )(cos theta- sec theta )=(1)/(tan theta + cot theta).

Prove that (sin theta- "cosec" theta )(cos theta- sec theta )=(1)/(tan theta + cot theta).

Prove that (sin theta- "cosec" theta )(cos theta- sec theta )=(1)/(tan theta + cot theta).

(cosec theta -sin theta ) (sec theta - cos theta ) (tan theta + cot theta ) = 1.

((sec theta+tan theta)(1-sin theta))/ (cosec theta(1+cos theta)(cosec theta-cot theta)) is equal to: ((sec theta+tan theta)(1-sin theta))/ (cosec theta(1+cos theta)(cosec theta-cot theta)) का मान किसके बराबर है?