[" he equation of a circle which touches the line "x+y=5" at "N(-2,7)" and cuts the "],[" icle "x^(2)+y^(2)+4x-6y+9=0" orthogonally,is - "]

The equation of a circle which touches the line x +y= 5 at N(-2,7) and cuts the circle x^2 + y^2 + 4x-6y + 9 = 0 orthogonally, is

The equation of a circle which touches the line x+y=5 at N(-2,7) and cuts the circle x^(2)+y^(2)+4x-6y+9=0 orthogonally,is

Find the equation of a circle, which touches the line x+ y = 5 at the point (-2, 7) and cuts the circle x^2+ y^2+ 4x - 6y +9 =0 orthogonally.

The radius of the circle which touches the line x+y=0 at M(-1,1) and cuts the circle x^(2)+y^(2)+6x-4y+18=0 orthogonally,is

The equation of the circle which passes through the origin,center lies on the line x+y=4 and cuts the circle x^(2)+y^(2)-4x+2y+4=0 orthogonally :