" (iv) "(x)/(2)+(2y)/(3)=-13+1

Solve for x and y : ( 3x )/( 2) - ( 5y )/( 3) = - 2, ( x)/(3) + ( y)/(2) = (13)/(6)

(2) (3x)/(2)-(5y)/(3)=-2 ; (x)/(3)+(y)/(2)=(13)/(6)

The straight lines (x-3)/(2)=(y+5)/(4)=(z-1)/(-13)and(x+1)/(3)=(y-4)/(5)=(z+2)/(2) are

Find the value of x and y (1)/(2x)+(1)/(3y)=2 (1)/(3x)+(1)/(2y)=(13)/(6)

Statement 1: The shortest distance between the lines (x)/(-3)=(y-1)/(1)=(z+1)/(-1) and (x-2)/(1)=(y-3)/(2)=((z+(13/7))/(-1)) is zero.Statement 2: The given lines are perpendicular.

From a point on x+2y-7=0 tangents are drawn to curve 13(x^(2)+y^(2)-2x+1)=(2x+3y-1)^(2) are perpendicular then the point is (a)(19,13) (b) (-19,13) (c) (19,-13) (d)(-19,-13)

If y = 2x + 3x ^ (2) + 4x ^ (3) + ......., then (y) / (2) - (1.3) / (2!) ((Y) / (2) ) ^ (2) + (1.3.5) / (3!) ((Y) / (3)) ^ (3) -...... oo =

Solve the following system of equations: (1)/(2x)+(1)/(3y)=2,quad (1)/(3x)+(1)/(2y)=(13)/(6)