Find the equation of the circle whose radius is 3 and which touches internally the circle `x^2+y^2-4x-6y=-12=0` at the point `(-1,-1)dot`

The equation to the circle whose radius is 3 and which touches internally the circle x^(2)+y^(2)-4x+6y-12=0" at this point (-1,1) is"

Centre of the circle whose radius is 3 and which touches internally the circle x^(2)+y^(2)-4x-6y-12=0 at the point (-1 -1) is

Centre of the circle whose radius is 3 and which touches internally the circle x^(2)+y^(2)-4x-6y-12=0 at the point (-1 -1) is

Centre of the circle whose radius is 3 and which touches internally the circle x^(2)+y^(2)-4x-6y-12=0 at the point (-1 -1) is

Centre of the circle whose radius is 3 and which touches internally the circle x^(2)+y^(2)-4x-6y-12=0 at the point (-1 -1) is

Solve the following:Find the co-ordinates of centre of the circle whose radius is 3 units and which touches internally to the circle x^2+y^2-4x-6y-12=0 at point (-1,-1).

Find the equation of the circle whose radius is 5 and which touches the circle x^2+y^2-2x-4y-20=0 externally at the point (5,5)dot

Find the equation of the circle whose radius is 5 and which touches the circle x^2+y^2-2x-4y-20=0 externally at the point (5,5) .