sin2 theta=(2tan theta)/(1+tan^(2)theta)

Show that (cos^(2)theta - sin^(2)theta)=(2tan theta)/((1- tan^(2)theta)) is not an identity .

By using above basic addition/ subtraction formulae, prove that (i) tan (A+B)=(tan A+tan B)/(1-tan A tan B) , (ii) tan (A-B)=(tan A-tanB)/(1+tan A tan B) (iii) sin2theta=2sintheta costheta , (iv) cos2theta=cos^(2)theta=1-2sin^(2)theta=2cos^(2)theta-1 (v) tan 2theta=(2 tan theta)/(1-tan^(2) theta)

By using above basic addition/ subtraction formulae, prove that (i) tan (A+B)=(tan A+tan B)/(1-tan A tan B) , (ii) tan (A-B)=(tan A-tanB)/(1+tan A tan B) (iii) sin2theta=2sintheta costheta , (iv) cos2theta=cos^(2)theta=1-2sin^(2)theta=2cos^(2)theta-1 (v) tan 2theta=(2 tan theta)/(1-tan^(2) theta)

By using above basic addition/ subtraction formulae, prove that (i) tan (A+B)=(tan A+tan B)/(1-tan A tan B) , (ii) tan (A-B)=(tan A-tanB)/(1+tan A tan B) (iii) sin2theta=2sintheta costheta , (iv) cos2theta=cos^(2)theta=1-2sin^(2)theta=2cos^(2)theta-1 (v) tan 2theta=(2 tan theta)/(1-tan^(2) theta)

Prove that : sin 2 theta= (2 tan theta)/(1+tan^2 theta) .

Taking theta=30^(@) , verify each of the following (i) sin 2theta=2sin theta cos theta (ii) cos theta=2cos^(2)theta-1=1-2sin^(2)theta (iii) tan2theta=(2tantheta)/(1-tan^(2)theta)

Prove that (1+sin2 theta)/(1-sin2 theta)=((1+tan theta)/(1-tan theta))^(2)

prove that :(1-sin2 theta)/(1+sin2 theta)=((1-tan theta)/(1+tan theta))^(2)

Prove that (1+sin2 theta)/(1-sin2 theta)=((1+tan theta)/(1-tan theta))^(2)

Solve cot theta = sin 2 theta by substituting sin 2 theta =( 2 tan theta )/( 1+tan^(2) theta ) and again by substituting sin 2 theta = 2 sin theta * cos theta and check whether the two answer are same or not .