If enthalpies of formation of `C_(2)H_(4)(g)1` and`H_(2)O(l)` at`25(@)C` and`1`atm pressure be `52,-394`and`-286kJmol^(-1)`respectively ,the enthalpy of combustion of `C_(2)H_(4)(g)`will be

If enthalpies of formation of C_(2)H_(4)(g)1 ,CO_(2) and H_(2)O(l) at 25(@)C and 1 atm pressure be 52,-394 and -286kJmol^(-1) respectively ,the enthalpy of combustion of C_(2)H_(4)(g) will be

The enthalpy of formation for C_(2)H_(4)(g) , CO_(2)(g) and H_(2)O(l) at 25^(@)C and 1 atm. Pressure be 52 , -394 and -286 kJ mol^(-1) respectively. The enthalpy of combustion of C_(2)H_(4)(g) will be

The enthalpy of formation for C_(2)H_(4)(g),CO_(2)(g) and H_(2)O(l) at 25^(@)C and 1 atm. Pressure are 52, -394 and -286 KJ mol^(-1) respectively. The entahlpy of combustion of C_(2)H_(4) will be :-

The standard enthalpy of formation of C_(2)H_(4)(l) , CO_(2)(g) and H_(2)O(l) are 52 , 394 and -286 kJ mol^(-1) respectively. Then the amount of heat evolved by burning 7g of C_(2)H_(4)(g) is

The molar enthalpies of combustion of C_(2)H_(2)(g), C("graphite") and H_(2)(g) are -1300,-394 , and -286 kJ mol^(-1) , respectively. The standard enthalpy of formation of C_(2)H_(2)(g) is

The molar enthalpies of combustion of C_(2)H_(2)(g), C("graphite") and H_(2)(g) are -1300,-394 , and -286 kJ mol^(-1) , respectively. The standard enthalpy of formation of C_(2)H_(2)(g) is

At 25^(@)C and 1 atm, heat of formation of C_(2)H_(4) (g), CO_(2)(g) and H_(2)O(l) are 52 " kJ mol"^(-1), -394 " kJ mol"^(-1) and -286 " kJ mol"^(-1) respectively. Calculate the heat of combustion of C_(2)H_(4)(g) .