Let :f:[-1,3]to R be defined as
`f(x)={{:(|x|+[x]",", -1lexlt1),(x+|x|",", 1lexlt2),(x+[x]",", 2lexle3):}`
Where [t] denotes the greatest integer less than or equal to t. then, f is continuous at :

Let f : [-1, 3] to R be defined as {{:(|x|+[x]", "-1 le x lt 1),(x+|x|", "1 le x lt 2),(x+[x]", "2 le x le 3","):} where, [t] denotes the greatest integer less than or equal to t. Then, f is discontinuous at

If f(x)=x-[x], where [x] is the greatest integer less than or equal to x, then f(+1/2) is:

If f(x)={(x[x], 0lexlt2),((x-1)[x], 2lexle3'):} , where [.] denotes the greatest integer function, then

Let f(x)=(x-[x])/(1+x-[x]), where [x] denotes the greatest integer less than or equal to x,then the range of f is

Let a function f : R to R be defined as f(x)={{:(sinx-e^(x),if,xle0),(a+[-x],if,0ltxlt1),(2x-b,if,xge1):} Where [x] is the greatest integer less than or equal to x. If f is continuous on R, then (a + b) is equal to:

Let f(x)=[x^(2)+1],([x] is the greatest integer less than or equal to x) . Ther

let f:R rarr R be given by f(x)=[x]^(2)+[x+1]-3, where [x] denotes the greatest integer less than or equal to x. Then,f(x) is

The function f(x)=(tan |pi[x-pi]|)/(1+[x]^(2)) , where [x] denotes the greatest integer less than or equal to x, is