[" Id is "0.5m^(3)." If it is hammered into a sheet "],[" s of the sheet."],[" ume "=((0.5)/(1000times10))m=((0.5times100times10)/(10000))mm]

5times1000+0times100+10+8times1 =

Solve: 0.5times10

" (f) (5^(6)times a^(7))/(5^(2)times a^(3)times(10)^(0))

Solve: 0.5times1000

The volume of a block of gold is 0.5m^(3). If it is hammered into a sheet to cover an area of 1 hectare,find the thickness of the sheet.

An iron of cube of side 10 cm is hammered into a rectangular sheet of thickness 0.5 cm. If the sides of the sheet are in the ratio 1:5, the sides are (a) 10 cm, 50 cm (b) 20 cm, 100 cm (c) 40 cm, 200 cm (d) None of these

Find the wavelength of electromagnetic waves of frequency 6 times 10^(12)Hz in free space having speed of 3 times 10^(8)m/s in free space. (a) 6 times 10^5m (b) 5 times 10^-5m (c) 2.5×10^5m (d) 1.5×10^5m

The value of 10+0+(9)/(100) + ( 5)/( 1000) is

A large charged metal sheet is placed in a uniform electric field, perpendicular to the electric field lines. After placing the sheet into the field, the electric field on the left side of the sheet is E_1 = 5 xx 10^5 Vm^(-1) and on the right it is E_2 = 3 xx 10^5 V m^(-1) . The sheet experiences a net electric force of 0.08 N. Find the area of one face of the sheet. Assume the external field to remain constant after introducing the large sheet. Use (1/(4piepsilon_0)) = 9 xx 10^(9) Nm^(2)C^(-2)

A large charged metal sheet is placed in a uniform electric field, perpendicular to the electric field lines. After placing the sheet into the field, the electric field on the left side of the sheet is E_1 = 5 xx 10^5 Vm^(-1) and on the right it is E_2 = 3 xx 10^5 V m^(-1) . The sheet experiences a net electric force of 0.08 N. Find the area of one face of the sheet. Assume the external field to remain constant after introducing the large sheet. Use (1/(4piepsilon_0)) = 9 xx 10^(9) Nm^(2)C^(-2)