A light source of wavelength `lambda` illuminates a metal and ejects photo-electrons with `(K.E.)_(max) =1.eV` Another light source of wavelength `(lambda)/(3)`, ejects photo-electrons from same metal with `(K.E.)_(max) = 4eV` Find the value of work function?

A light source of wavelength lambda illuminates a metal and ejects photoelectron with (KE)^(max) = 1 eV. Another light source of wave length (lambda)/(3), ejects photoelectrons from same metal with (KE)^(max)=5 eV. Find the value of work function (eV) of metal.

A light source of wavelength lambda illuminates a metal and ejects photoelectron with (KE)^(max) = 1 eV. Another light source of wave length (lambda)/(3), ejects photoelectrons from same metal with (KE)^(max)=5 eV. Find the value of work function (eV) of metal.

A light source of wavelength lambda illuminates a metal and ejects photoelectron with (KE)^(max) = 1 eV. Another light source of wave length (lambda)/(3), ejects photoelectrons from same metal with (KE)^(max)=5 eV. Find the value of work function (eV) of metal.

A radiation of wavelength lamda illuminates a metal and ejects photoelectrons of maximum kinetic energy of 1eV. Aother radiation of wavelength (lamda)/(3) , ejects photoelectrons of maximum kinetic energy of 4eV. What will be the work function of metal?

If threshold wavelength (lambda_(0)) for ejection of electron from metal is 330 nm, then work function for the photoelectron emission is

If the threshold wavelength (lambda_(0)) for ejection of electron from metal is 330 nm, then work function for the photoelectric emission is:

If the threshold wavelength (lambda_(0)) for ejection of electron from metal is 330 nm, then work function for the photoelectric emission is:

If the threshold wavelength (lambda_(0)) for ejection of electron from metal is 350 nm then work function for the photoelectric emission is