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Let `a_1, a_2, a_3...a_n` be in AP such that `sum_(k=0)^12(a_(4k+1))=416` and `a_9+a_43=66` If `a_1^2+a_2^2+...+a_17^2=140m` then m is equal to
A. 66
B. 68
C. 34
D. 33

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