A conducting rod `AC` of length `4l` is rotate about a point `O` in a uniform magnetic field `vecB` directed into the paper. `AO=l` and `OC=3l`. Then

A conducting rod AC of length 4l is rotated about point O in a uniform magnetic field vec(B) directed into the plane of the paper. AO = l and OC = 3l . Find V_(A) - V_(C) .

A conducting rod AC of length 4l is rotated about point O in a uniform magnetic field vec(B) directed into the plane of the paper. AO = l and OC = 3l . Find V_(A) - V_(C) .

A conducting rod OA of length l is rotated about its end O with an angular velocity omega in a uniform magnetic field directed perpendicualr to the rotation. Find the emf induced in the rod, between it's ends.

A conducting rod AB of length l is rotated about point O with an angular velocity velocity omega in a uniform magnetic field (B_0) directed perpendicular into the plane of rotation as shown in the figure. The value of V_B - V_A is

A conducting rod of length / is rotating about point Pin a uniform transverse magnetic field B_0 as shown in the figure. If angular speed of the rod is ω_0 then the magnitude of induced emf across the ends of the rod will be (PA = 2l/3 and PB = l/3)

A small conducting rod of length l, moves with a uniform velocity v in a uniform magnetic field B as shown in fig __

A small conducting rod of length l, moves with a uniform velocity v in a uniform magnetic field B as shown in fig __

A conducting rod of length l is rotating with constant angular velocity omega about point O in a uniform magnetic field B as shown in the figure . What is the emf induced between ends P and Q ?