Home
Class 12
CHEMISTRY
For diprotic selenous acid (H(2)SeO(3)) ...

For diprotic selenous acid `(H_(2)SeO_(3))` equilibrium constants `K_(a)1` and `K_(a)2` are `3.0xx10^(-3) and 5.0xx10^(-8)` respectively. `[OH – ]` of 0.30 M solution of selenous acid is :

Promotional Banner

Similar Questions

Explore conceptually related problems

Selenious acid (H_(2)SeO_(3)) , a diprotic acid has K_(a1)=3.0xx10^(-3) and K_(a2)=5.0xx10^(-8) . What is the [OH^(-)] of a 0.30 M solution of selenious acid?

Selenious acid (H_(2)SeO_(3)) , a diprotic acid has K_(a1)=3.0xx10^(-3) and K_(a2)=5.0xx10^(-8) . What is the [OH^(-)] of a 0.30 M solution of selenious acid?

K_(1) & K_(2) for oxalic acid are 6.5 xx 10^(-2) and 6.1 xx 10^(-5) respectively . What will be the [OH^(-)] in a 0.01 M solution of sodium oxalate

K_(1) & K_(2) for oxalic acid are 6.5 xx 10^(-2) and 6.1 xx 10^(-5) respectively . What will be the [OH^(-)] in a 0.01 M solution of sodium oxalate

K_(a_1) and K_(b_1) of oxalic acid are 6 xx 10^(-2) and 7.2 xx 10^(-5) respectively. Calculate the pH of 0.06 M oxalic acid solution

Selenious acid (H_(2)SeO_(3)) ,a diprotoc acid has Ka_(1)=10^(-6) and Ka_(2)=10^(-8) respectively. Appoximate pH of 0.01M NaHSeO_(3) is given by :-

Selenious acid (H_(2)SeO_(3)) ,a diprotoc acid has Ka_(1)=10^(-6) and Ka_(2)=10^(-8) respectively. Appoximate pH of 0.01M NaHSeO_(3) is given by :-

The first and second dissociation constants of an acid H_(2)A are 1.0xx10^(-5) and 5.0xx10^(-10) respectively. The overall dissociation constant of the acid will be :