The eccentricity of the conic `5/r=2 + 3 costheta + 4 sintheta` is

Find sintheta such that 3costheta+4sintheta=4 .

The parametric representation of a point on the ellipse whose foci are (3,0) and (-1,0) and eccentricity 2//3 , is a) (1+3costheta,sqrt(3)sintheta) b) (1+3costheta,5sintheta) c) (1+3costheta,1+sqrt(5)sintheta) d) (1+3costheta,sqrt(5)sintheta)

If costheta+sintheta=sqrt(2)costheta , then costheta-sintheta is

If (sintheta+costheta)/(sintheta-costheta)=3 and theta is an acute angle, then the value of (3sintheta+4costheta)/(8costheta-3sintheta) is

If 3 cot theta =4, " write the value of " ((2costheta+ sintheta ))/((4costheta- sintheta)).

Sintheta + Costheta = 2 Sintheta - Costheta = ?

If 3cottheta=1 , then find the value of (3costheta-4sintheta)/(5sintheta+4costheta) .

If 5 tan theta =4, " write the value of " ((costheta- sintheta ))/((costheta+ sintheta)).

Prove that all lines represented by the equation (2costheta+3sintheta)x+(3costheta-5sintheta)y=5costheta-2sintheta …(1) pass through a fixed point and its reflection in the line x+y=sqrt2 ? Prove that all lines through reflection point can be represented by the equation (2costheta+3sintheta)x+(3costheta-5sintheta)y= (sqrt2-1)(5costheta-2sintheta) ....(2)