A hyperbola has center at origin and passing through `(4-2sqrt(3))` and having directrix `5x=4sqrt(5)` then eccentricity of hyperbola (e) satisfy the equation.

If a directrix of a hyperbola centred at the origin and passing through the point (4,-2 sqrt(3)) " is " 5x=4sqrt(5) and its eccentricity is e, then

If a directrix of a hyperbola centred at the origin and passing through the point (4,-2 sqrt(3)) " is " 5x=4sqrt(5) and its eccentricity is e, then

If a directrix of a hyperbola centred at the origin and passing through the point (4,-2 sqrt(3)) " is " 5x=4sqrt(5) and its eccentricity is e, then

One of the foci of the hyperbola is origin and the corresponding directrix is 3x + 4y + 1=0 .The eccentricity of the hyperbola is sqrt 5 .The equation of the hyperbola is

A hyperbola has its centre at the origin, passes through the point (4, 2) and has transverse axis of length 4 along the x-axis. Then the eccentricity of the hyperbola is

A hyperbola has its centre at the origin, passes through the point (4, 2) and has transverse axis of length 4 along the x-axis. Then the eccentricity of the hyperbola is

A hyperbola has its centre at the origin, passes through the point (4, 2) and has transverse axis of length 4 along the x-axis. Then the eccentricity of the hyperbola is

A hyperbola has its centre at the origin, passes through the point (4, 2) and has transverse axis of length 4 along the x-axis. Then the eccentricity of the hyperbola is

if the eccentricity of the hyperbola is sqrt2 . then find the general equation of hyperbola.