The work done in rotating the magnet form the direction of uniform field to the opposite direction to the field is`W`. The work done in rotating the magnet form the field direction to half the maximum couple position is

The work done in rotating a magnet of magnetic moment 2A-m^(2) in a magnetic field to opposite direction to the magnetic field, is

The work done in turning a magnet normal to field direction from the direction of the field is 40xx10^(-6)J . The kinetic energy attained by it when it resches the field direction when released is

If 'W' Joule is the work done in rotating the magnet from the field direction to a position that makes an angle 60' with the direction of the field, the torque required to hold the magnet in that direction is

Find expression for work done in rotating a bar magnet in a uniform magnetic field.

38.If 'W' Joule is the work done in rotating the magnet from the field direction to a position that makes an angle 60^(@) with the direction of the field,the torque required to hold the magnet in that direction is 1) wN-m 2) (W)/(2)N-m 3) (W)/(sqrt(3))N-m, 4) sqrt(3)WN-m

A bar magnet of magnetic moment M is aligned parallel to the direction of a uniform magnetic field B. Calculate work done to align the magnetic moment normal to field direction?