In the figure a capacitor is filled with dielectrics `K_(1)`,` K_(2)` and `K_(3)`. The resultant capacitance is

In the figure a capacitor id filled with dielectric. The resultant capacitance is

In the figure, a capacitor is field with dielectrics. The resultant capacitance is

In the figure, a capacitor is field with dielectrics. The resultant capacitance is

The capacitance of a parallel plate capacitor with plate area A and separation d is C . The space between the plates in filled with two wedges of dielectric constants K_(1) and K_(2) respectively. Find the capacitance of resulting capacitor.

The capacitance of a parallel plate capacitor with plate area A and separation d is C . The space between the plates in filled with two wedges of dielectric constants K_(1) and K_(2) respectively. Find the capacitance of resulting capacitor.

Space between plates of a capacitor (of area A ) is filled two dielectric slab of dielectric constant k_(1) and k_(2) .The capacitor is connected to battery of emf E then the charge stored on the capacitor will be (d_(2)=1.5d_(1) and k_(1)=2k_(2))

Space between plates of a capacitor (of area A ) is filled two dielectric slab of dielectric constant k_(1) and k_(2) .The capacitor is connected to battery of emf E then the charge stored on the capacitor will be ( d_(2)=1.5d_(1) and k_(1)=2k_(2) )

A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is A "metre"^(2) and the separtion is t metre. The dielectric constants are K_(1) and K_(2) , respectively. Its capacitance in farad will be