If `cos3x+cos6x=cos4x+cos5x,` then the solution set is

If cos3x+cos6x=cos4x+cos5x , then solution set is

2cos x-cos3x-cos5x=

cos4x cos8x-cos5x cos9x=0 if

Solve cos3x-cos4x=cos5x-cos6x

1+ cos 2x+ cos4x + cos 6x=

cos x+cos2x+cos3x+cos4x=0, has number of solutions:

The expression (cos6x+6cos4x+15cos2x+10)/(cos5x+5cos3x+10cosx) = lambdacosx , then the value of lambda is ___________.

The expression (cos6x+6cos4x+15cos2x+10)/(cos5x+5cos3x+10cosx) = lambdacosx , then the value of lambda is ___________.

f(x)=(10cos x+5cos3x+cos5x)/(cos6x+6cos4x+15cos2x+10) then find the value of (0)+f'(0)+f'(0)

sin3x + sinx = cos6x + cos4x