If a directrix of a hyperbola centred at the origin and passing through the point `(4,-2 sqrt(3)) " is " 5x=4sqrt(5)` and its eccentricity is e, then

Equation of the ellipse with centre at origin, passing through the point (-3,1) and e=sqrt((2)/(5)) is

A hyperbola has center at origin and passing through (4-2sqrt(3)) and having directrix 5x=4sqrt(5) then eccentricity of hyperbola (e) satisfy the equation.

A hyperbola, centred at the origin, has transverse axis 2a. If it passes through a given point ( x_(1), y _(1)), then its eccentricity is

An ellipse passing through (4sqrt2, 2 sqrt 6) foci at (-4,0) and (4,0). Its eccentricity is

An ellipse passing through the point " (2sqrt(13),4) " has its foci at " (-4,1) " and " (4,1) " .Then its eccentricity is

An ellipse passing through (4sqrt(2), 2sqrt(6)) has foci at (-4, 0) and (4, 0). Its eccentricity is

An ellipse passing through (4sqrt(2),2sqrt(6)) has foi at (-4,0) and (4,0). Then,its eccentricity is

Eccentricity of the hyperbola passing through (3,0) and (3 sqrt(2),2) is

The eccentricity of a hyperbola passing through the points (3,0), (3 sqrt2,2) will be