if `A=[[cos,sinx,0],[-sinx,cosx,0],[0,0,1]]=f(x)` then `A^-1`

If A=[{:(cosx,sinx,0),(-sinx,cosx,0),(0,0,1):}] =f(x), then A^(-1) is equal to

If f(x)=[[cosx,-sinx,0],[sinx,cosx,0],[0,0,1]] Find f(-x)

Select and write the correct answer from the given alternatives in each of the following:If f(x)=[[cosx,-sinx,0],[sinx,cosx,0],[0,0,1]] then f(x+y) is equal to

If F(x)=[[cosx,-sinx,0],[sinx,cosx,0],[0,0,1]] Show that F(x)F(y)=F(x+y)

If F(x)=[[cosx,-sinx,0],[sinx,cosx,0],[ 0, 0, 1]] , show that F(x) F(y) = F(x + y) .

If A=f(x)=[(cosx, sinx, 0),(-sinx, cosx,0),(0,0,1)], then the value of A^-1= (A) f(x) (B) -f(x) (C) f(-x) (D) -f(-x)

F(x)=[[cosx,-sinx,0],[sinx,cosx,0],[0,0,1]] and G(x)=[[cosx,0,sinx],[0,1,0],[-sinx,0,cosx]], then [F(x)G(y)]^(-1) is equal to (A) F(-x)G(-y) (B) F(x-1)G(y-1) (C) G(-y)F(-x) (D) G(y^(-1))F(x^(-1))

If f(x) = [(cos x , - sinx,0),(sinx,cosx,0),(0,0,1)] then show f(x) . f(y) = f(x+y)

If f(x) = [(cos x , - sinx,0),(sinx,cosx,0),(0,0,1)] then show f(x) . f(y) = f(x+y)