[" 17.zific "y,zbar(ap)" watol "ddot z" am "z=ax" at Rerea ablute "],[qquad (d^(2)y)/(dx^(2))=a^(2)(d^(2)y)/(dz^(2))]

If y^(2)=4ax , then the value of (d^(2)y)/(dx^(2))*(d^(2)x)/(dy^(2)) is -

If x=e^(z) then x^(2)*(d^(2)y)/(dx^(2)) is

If y=e^(ax)sinbx, then (d^(2)y)/(dx^(2))-2a(dy)/(dx)+a^(2)y=

If y^(2) = ax^(2) + b , " then " (d^(2)y)/( dx^(2))

If y^(2) = ax^(2) + b , " then " (d^(2)y)/( dx^(2))

If x=1/z and y=f(x), then prove that, (d^2f)/(dx^2)=2z^3dy/dz+z^4(d^2y)/(dz^2)

If y^2=4ax then the value of (d^2y)/(dx^2) is-

Putting logx=z show that, x^2(d^2y)/(dx^2)=(d^2y)/(dz^2)-dy/dz .

If the dependent variable y is changed to z by the substitution y=tan z and the differential equation (d^(2)y)/(dx^(2))=1+(2(1+y))/(1+y^(2))((dy)/(dx))^(2) is changed to (d^(2)z)/(dx^(2))=cos^(2)z+k((dz)/(dx))^(2), then the value of k equal to

If x=4z^(2)+5,quad y=6z^(2)+7z+3, find (d^(2)y)/(dx^(2))