The line `(x-3)/1=(y-4)/2=(z-5)/2` cuts the plane `x+y+z=17` at

The distance between the point (3,4,5) and the point where the line (x-3)/1=(y-4)/2=(z-5)/2 meets the plane x+y+z=17 is

The distance between the point (3,4,5) and the point where the line (x-3)/1=(y-4)/2=(z-5)/2 meets the plane x+y+z=17 is

The coordinates of the point where the line (x-3)/(1)=(y-4)/(2)=(z-5)/(2) meets the plane x+y+z=17 are -

Distance from the point (3,4,5) to the point where the line (x-3)/1 =(y-4)/2 = (z-5)/2 meets the plane x+y+z=17 is

Find the distance of the point of intersection of the line (x-3)/1=(y-4)/2=(z-5)/2 and the plane x + y + z = 17 from the point (3, 4, 5).

Find the distance of the point of intersection of the line (x-3)/(1)=(y-4)/(2)=(z-5)/(2) and the plane x+y+z=17 from the point (3,4,5) .

Find the angle betweenthe line (x-2)/-1=(y+3)/2=(z+4)/3 and the plane 2x-3y+z=5 .

Find the image of the line (x-1)/3=(y-2)/4=(z-3)/5 on the plane x-2y+z+2=0 .

The image of the line (x-1)/3=(y-3)/1=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line

The angle between the line (x-2)/1=(y+3)/-2=(z+4)/-3 and the plane 2x-3y+z=5 is