If rod is initially compressed by `Deltal` length then what is the strain on the rod when the temperature
(a) is increased by `Delta theta` (b) is decreased by `Delta theta`

Temperature of plate is increased by Delta theta then find new

The moment of inertia of a rod about its perpendicular bisector is I . When the temperature of the rod is increased by Delta T , the increase in the moment of inertia of the rod about the same axis is (Here , alpha is the coefficient of linear expansion of the rod )

The moment of inertia of a rod about its perpendicular bisector is I . When the temperature of the rod is increased by Delta T , the increase in the moment of inertia of the rod about the same axis is (Here , alpha is the coefficient of linear expansion of the rod )

A brass rod of length 1 m is fixed to a vertical wall at one end, with the other end keeping free to expand. When the temperature of the rod is increased by 120^@C , the length increases by 3 cm . What is the strain?

A brass rod of length 1 m is fixed to a vertical wall at one end, with the other end keeping free to expand. When the temperature of the rod is increased by 120^@C , the length increases by 3 cm . What is the strain?

If the temperature of a rod is increased from theta " to " theta^(') thermal strain in it will depend on

The moment of inertia of a rod about its perpendicular bisector is l, when temperature of rod is increased by Delta T, the increase in the moment of inertia of the rod about same axis ( gamma = temperature coefficient of volume expansion)

The moment of inertia of a rod about its perpendicular bisector is l, when temperature of rod is increased by Delta T, the increase in the moment of inertia of the rod about same axis ( gamma = temperature coefficient of volume expansion)