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[" lution of the differential equitation "(1+y^(2))+(x-e^(ln^(-1)y))(dy)/(dx)=0" is "],[[(x-2)=Ce^(-2ln^(-1)y)," (B) "2xe^(ln^(-1)y)=e^(2ln^(-1)y)+C],[xe^(ln^(-1)y)=tan^(-1)y+C," (D) "xe^(2ln^(-1)y)=e^(ln^(-1)y)+C]]

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