The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

The horizontal range is equal to two times maximum height of a projectile. The angle of projection ofthe projectile is:

Assertion: For projection angle tan^(-1)(4) , the horizontal range and the maximum height of a projectile are equal. Reason: The maximum range of projectile is directely proportional to square of velocity and inversely proportional to acceleration due to gravity.

Assertion: For projection angle tan^(-1)(4) , the horizontal range and the maximum height of a projectile are equal. Reason: The maximum range of projectile is directely proportional to square of velocity and inversely proportional to acceleration due to gravity.

(A): For projection angle tan^(-1)4 , the horizontal range and the maximum height of a projectile are equal. (R): The maximum range of projectile is directly proportional to square of velocity and inversely proportional to acceleration due to gravity.

If R and H represent horizontal range and maximum height of the projectile, then the angle of projection with the horizontal is

If R and H represent horizontal range and maximum height of the projectile, then the angle of projection with the horizontal is

The horizontal range is four times the maximum height attained by a projectile . The angle of projection is