+(9)/(4)int_(-2)^(1)(dx)/((x-alpha)(beta-x)')beta>alpha

Evaluate: int(1)/((x-alpha)(beta-x))dx,(beta>alpha)

Evaluate : int(dx)/((x-alpha)(beta-x))beta gt alpha

int(dx)/(sqrt((x-alpha)(beta-x)))

Evaluate: int1/((x-alpha)(beta-x))dx ,(beta>alpha)

Evaluate: int1/((x-alpha)(beta-x))dx ,(beta>alpha)

int (dx)/(sqrt((x-alpha)(x-beta)))

Putting x=alphacos^(2)theta+betasin^(2)theta show that, int_(alpha)^(beta)sqrt((x-alpha)(beta-x))dx=((beta-alpha)^(2)pi)/(8)

Evaluate: int_(alpha)^(beta)(dx)/(sqrt((x-alpha)(beta-x)))dx

int(dx)/((x-beta)sqrt((x-alpha)(beta-x))) is

The value of the integral int_alpha^beta (1)/(sqrt((x-alpha)(beta-x)))dx " for "beta gt alpha , is