if `y=tan^-1((sinx)/(1+cosx))` prove that `(dy)/(dx) = 1 / 2`

If y=tan^(-1)(cosx/(1+sinx)), then prove that dy/dx=-1/2

If y="tan"^(-1)((cosx-sinx)/(cosx+sinx)) , then (dy)/(dx)=

y= tan^(-1)((sinx)/(1+cosx)) Find dy/dx

If y = Tan^(-1)((cosx)/(1+sinx)) then (dy)/(dx) =

If y=tan^(-1)((sinx+cosx)/(cosx-sinx)) , then (dy)/(dx) is equal to (a) 1/2 (b) 0 (c) 1 (d) none of these

If y=tan^(-1)[(sinx+cosx)/(cosx-sinx)] then (dy)/(dx) is

If y=tan^(-1)[(sinx+cosx)/(cosx-sinx)] then (dy)/(dx) is

If y=tan^(-1)((sinx+cosx)/(cosx-sinx))," then "(dy)/(dx)" at "x=(pi)/(4)

If y=tan^(-1)(( sin x + cosx)/(cosx-sinx)) then (dy)/(dx) is equal to

If y = tan^(-1){(cos x)/(1 + sinx)} " then " (dy)/(dx) = ?