[4x-3y=3],[3x-5y=7]

Solve: 2x-3y=3 and 4x-5y=7

The equations of sides of a triangle are x+3y=0 , 4x-3y=5 and 3x-y=0. Then the line 6x-7y=0 passes through the __________ of the triangle.

3x-4y=-7,5x-2y=0

2x+3y=3 4x+5y=3

solve for x and y 2x-3y+7=0 3x+4y-5=0

Add: 4xy+5x+7y, -4xy-y-3x, 3xy-3y+2x

The minimum value of p for which the lines 3x-4y=2, 3x-4y=12, 12x+5y=7 and 12x+5y=p constitute the sides of a rhombus is

The minimum value of p for which the lines 3x-4y=2, 3x-4y=12, 12x+5y=7 and 12x+5y=p constitute the sides of a rhombus is

The maximum value of p for which the lines 3x-4y=2, 3x-4y=12, 12x+5y=7 and 12x+5y=p constitute the sides of a rhombous is