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tan alpha + 2 tan 2alpha + 4 tan4alpha +...

` tan alpha + 2 tan 2alpha + 4 tan4alpha + 8 cot8alpha` is equal to :

Text Solution

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`8cot8alpha`
`8(cot^24alpha-1)/(2cot4alpha)`
`4cot4alpha-4tan4alpha`
`4(cot^2 2alpha-1)/(2cot2alpha)-4tan4alpha`
`2cot2alpha-2tan2alpha-4tan4alpha`
`cotalpha-tanalpha-2tan2alpha-4tan4alpha`
`=cotalpha`
option c is correct.
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