For the arrangement shown in the switch is closed at t =0. The time after which the current becomes `2.5muAS` is given by (take in 2 =0.69)

The switch is closed at t=0. Find time after which voltage across capacitor becomes 50 V. (take ln 2 = 0.6)

In the circuit shown in figure the switch S is closed at t = 0. A long time after closing the switch

In the circuit as shown in figure the switch is closed at t = 0 . A long time after closing the switch

In given LR circuit the switch S is closed at time t=0 then

In given LR circuit the switch S is closed at time t=0 then

In the circuit shown in figure switch S is closed at time t=0 Current I from the battery at time t is given by

In the circuit shown in figure switch S is closed at time t=0 Current I from the battery at time t is given by

In adjacent circuit, switch S is closed at t = 0. The time at which current in the circuit becomes half of the steady current is

For the arrangement shown in the figure, the switch is closed at t = 0 . C_2 is initially uncharged while C_1 has a charge of 2muC (a) Find the current comingn out of the battery just after the switch is closed. (b) Find the charge on the capacitors in the steady state condition.

For the arrangement shown in the figure, the switch is closed at t = 0 . C_2 is initially uncharged while C_1 has a charge of 2muC (a) Find the current comingn out of the battery just after the switch is closed. (b) Find the charge on the capacitors in the steady state condition.