[" 27.If "tan alpha=(1)/(sqrt(x(x^(2)+x+1))),tan beta=(sqrt(x))/(sqrt(x^(2)+x+1))" and "tan gamma=sqrt(x^(-3)+x^(-2)+x^(-1))" then "alpha+beta=],[[" 1) "gamma," 2) "2 gamma," 3) "-gamma," 4) "gamma/2]]

if tanalpha=1/(sqrt(x(x^2+x+1))), tanbeta=(sqrtx)/(sqrt(x^2+x+1) and tangamma=sqrt(x^-3+x^-2+x^-1) then alpha+beta=

If tan A= 1/(sqrt(x(x^2+x+1))), tan B = sqrtx/(sqrt (x^2+ x+ 1)) and tan C = sqrt(x^(-3)+x^(-2)+x^(-1)) , prove that A+B=C.

If tan alpha = (1)/(sqrt (x (x ^(2) + x + 1))). tan beta = (sqrtx)/(sqrt (x ^(2) + x +1))and tan y = (x ^(-3) + x ^(-2)+ x ^(-1)) ^(1//2), then for x gt 0

If tan alpha=(1)/(sqrt(x(x^(2)+x+1))),tan beta=(sqrt(x))/(sqrt(x^(2)+x+1)) and tan gamma=sqrt((1)/(x^(3))+(1)/(x^(2))+(1)/(x)) be such that l alpha+m beta+n gamma=0 then the value of l^(3)+m^(3)+n^(3)-3lmn is

If tan alpha = 1/sqrt(x(x^2+x+1)),tan beta=sqrtx/sqrt(x^2+x+1) and tan gamma=sqrt(1/x^3+1/x^2+1/x) be such that lalpha+mbeta+ngamma=0 then the value of l^3+m^3+n^3-3lmn is

tan^(-1)(x+sqrt(1+x^(2)))=

If alpha=tan^(-1)((sqrt(3)x)/(2y-x)),beta=tan^(-1)((2x-y)/(sqrt(3y)))" then "alpha-beta=

tan[2Tan^(-1)((sqrt(1+x^(2))-1)/x)]=

tan^(-1)((sqrt(1+x^(2))+sqrt(1-x^(2)))/(sqrt(1+x^(2))-sqrt(1-x^(2))))