[" The equation "],[sin theta+sqrt(3)cos theta=6x-x^(2)-11,0<=theta<=4 pi],[x in R" hold "(s)" good for "]

Solve for x and theta(0

sin theta + sqrt(3)cos theta = 6x - x^(2) - 11 , 0lt=thetalt=4pi x""in R holds for :

sin theta+sqrt(3)cos theta=6x-x^(2)-11,0<=4 theta pi,x in R hold for no values of x and theta one value of x and two values of theta two values of x and two values of theta two point of values of (x,theta)

The solution set of the equation 4 "sin" theta "cos" theta- 2 "cos" theta -2sqrt(3) "sin" theta + sqrt(3) =0 " in the interval" (0, 2 pi) , is

The solution set of the equation 4 "sin" theta "cos" theta- 2 "cos" theta -2sqrt(3) "sin" theta + sqrt(3) =0 " in the interval" (0, 2 pi) , is

sin theta+sqrt(3)cos theta=6y-y^(2)-11,theta in[0,4 pi],y in R holds for

If beta is one of the angles between the normals to the ellipse, x^2+3y^2=9 at the points (3 cos theta, sqrt(3) sin theta)" and "(-3 sin theta, sqrt(3) cos theta), theta in (0,(pi)/(2)) , then (2 cos beta)/(sin 2 theta) is equal to:

If beta is one of the angles between the normals to the ellipse, x^2+3y^2=9 at the points (3 cos theta, sqrt(3) sin theta)" and "(-3 sin theta, sqrt(3) cos theta), theta in (0,(pi)/(2)) , then (2 cot beta)/(sin 2 theta) is equal to:

Solve the following equation: \ 3cos^2theta-2\ sqrt(3)sinthetacostheta-3sin^2theta=0