The distance between the two end-points of the wings of an aeroplane is 5 m and the aeroplane is flying parallel to earth's surface with a velocity of 360 km `h^(-1)`. If the geomagnetic intensity is `4xx10^(-4)Wb . m^(-2)` and the angle of dip at that place is `30^(@)`, determine the emf induced between the two end-points of the wings.

Explanation

While flying horizontally, the wings of the aeroplane cuts the vertical component of earth's magnetic field normally and hence, an emf is induced between the two ends of the wings.
This induced emf, `e=Blvsintheta`
Here, `B=4xx10^(-4)Wb.m^(-2),l=5m`
`v=360km.h^(-1)=360xx(5)/(18)m.s^(-1)=100m.s^(-1)`
and `theta=30^(@)`
`therefore e=4xx10^(-4)xx5xx100xxsin30^(@)=0.1V`