The mutual inductance between two adjacent coils is 1.5 H. If the current in the primary coil changes from 0 to 20 A in 0.05 s, determine the average emf induced in the secondary coil. If the number of turns in the secondary coil is 800, what change in flux will be observed in it?

Explanation

The average value of induced emf,
`e=-M(DeltaI)/(Deltat)=-1.5xx((20-0))/(0.05)=-(1.5xx20)/(0.05)=-600V`
Hence, the magnitude of the induced emf = 600 V.
Again, from the relation `phi=MI` we get,
change in flux, `Deltaphi=M.DeltaI=1.5xx(20-0)=30Wb`.