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When current in a coil changes from +2A ...

When current in a coil changes from `+2A` to `-2A` in 0.05 s, an emf of 8 V is induced in the coil. Determine the self-inductance of the coil.

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Verified by Experts

We know that, `e=-L(DeltaI)/(Deltat)`
`therefore` Self-inductance of the coil, `L=-(eDeltat)/(DeltaI)=-(8xx0.05)/(-2-(+2))=0.1H`
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CHHAYA PUBLICATION-ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT-CBSE SCANNER
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