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Find the amount of stored energy within ...

Find the amount of stored energy within a coil of inductance 10mH due to a current of 50mA through it.

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`1.25xx10^(-5)J`
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Find out the energy stored in a coil of self inductance L due to a current I through it.

What will be the self-inductance of a solendoid of length 1m, diameter 12cm and number of turns 4000? How much energy will be stored in its magnetic field due to a current of 2A through it? (mu_(0)=4pixx10^(-7)H.m^(-1)) .

Knowledge Check

  • If two physical quantities a and b are related by the equation a= kb where k is dimensionless constant, then the principle of dimensional homogeneity demands that a and b have the same dimension. However the proportionality constant k cannot be determined by dimensional analysis only. It may at most be written that a prop b if a and b are of the same dimension. A coil of inductance L stores an amount of energy (1)/(2)Ll^(2) when a current I passes through it. The dimension of L is

    A
    `ML^(2)T^(-1)l^(2)`
    B
    `ML^(2)T^(-1)l^(-2)`
    C
    `ML^(2)T^(-2)l^(2)`
    D
    `ML^(2)T^(-2)l^(-2)`

  • The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance

    A
    1.389 H
    B
    138.88 H
    C
    0.138 H
    D
    13.89 H

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    A straight solenoid of length 50 cm and across sectional area 1cm^(2) has a self-inductance of 10^(-5)H . If a current of 100 mA passes through it, what will be the magnetic field along its axis?

    An alternating emf of E=20sin 1000tV is applied on a circuit containing a pure resistance of 25Omega in series with a coil of self-inductance 40 mH and resistance 15Omega . Find out the phase difference between E and the current I.

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    Derive the expression for energy stored in an inductor of coefficient of self-inductance L carrying current i_(0) .

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