An aeroplane is flying horizontally from west to east with a velocity of 900 km/h. Calculate the potential difference developed between the ends of its wings having a span of 20 m. The horizontal component of the Earth's magnetic field is `5xx10^(-4)T` and the angle of dip is `30^(@)`.

Explanation

Potential difference between the wings of the aeroplane,
`e=Bsin30^(@).l.v`
`l=20m,v=900km//h=900xx(5)/(18)=250m.s^(-1)`
`H=Bcos30^(@)or,B=(H)/(cos30^(@))`
`therefore e=Htan30^(@).l.v=5xx10^(-4)xx(1)/(sqrt(3))xx20xx250`
`=1.44V`