`60muF` capacitor to a 110 V, 60 Hz ac supply. Determine the rms value of the current in the circuit. What is the net power absorbed by the circuit over a complete cycle?

Explanation

`I_(rms)=V_(rms)/X_C`
where, `X_C=1/(2pifC)=1/(2pitimes60times60times10^-6)Omega`
and `V_(rms)=110V`
`thereforeI_(rms)=110(2pitimes60times60times10^-6)A=2.49A`
The net power absorbed is zero as in case of a ideal capacitor there is no power loss.