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An inductor 20mH, a capacitor 100muF and...

An inductor 20mH, a capacitor `100muF` and a resistor `50Omega` are connected in series across a source of emf V=10sin314t. The power loss in the circuit is

A

2.74 W

B

0.43 W

C

0.79 W

D

1.13 W

Text Solution

Verified by Experts

The correct Answer is:
C
`Z=sqrt(R^2+(omegaL-1/(omegaC))^2)`
`=sqrt((50)^2+[314times20times10^-3-1/(314times100times10^-6)]^2)`
`=56.16Omega`
The power loss in the circuit,
`P=(V_(rms)/Z)^2.R=((10/sqrt2)/56.16)^2times50=0.79W`
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