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Without making any other change, find the value of the additional capacitor `C_1`, to be connected in parallel with the capacitor C, in order to make the power factor of the circuit unity.

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To make power factor of the circuit unity,

`X_C=X_L`
`therefore1/(omega(C+C_1))=100`or,`1/(1000(C+C_1))=100`
or, `C+C_1=1/10^5`
or,`C_1=1/10^5-C=10^-5-0.2times10^-5=0.8times10^-5`
or, `C_1=8muF`
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