The total cost of producing `x` radio sets per day is `R sdot((x^2)/4 35 x+25)` and the price per set at which they may be sold is `R sdot(50-x/2)dot` Find the daily output to maximize the total profit.

The total cost of producing x radio sets per day is Rs.((x^(2))/(4)35x+25) and the price per set at which they may be sold is Rs.(50-(x)/(2)). Find the daily output to maximize the total profit.

The total cost of producing x transistor radio sets per day is (1/4x^2+35x+25) Rs and the selling price of each is (50-x/2) Rs. To obtain maximum profit the dialy output should be

The total cost of making n pocket radios per day is Rs{(n^(2))/(4)+35n+25 and the rate at which they may be sold to a distributor is Rs{(1)/(2)(100-n)}. For amaximum total profit,the daily output should be many of a small town has 500

Total cost of producing x items is Rs(x^(2)+10x+12) and selling price of each is Rs(330-x) . Then output for maximum profit must be

If the total cost function of producing x units of a commodity is given by 360 – 12x +2x^(2) , then the level of output at which the total cost is minimum is

Total cost of producing x items is Rs x^(2)/(4)+25x-50 and selling perice of each is Rs 100 -(x)/(4) . The output for maximum profit must be