0.44 gm of organic compound `C_(x) H_(y)` O which occupied 224 ml at NTP and on combustion gave 0.88 gm `CO_(2)`. The ratio of X to Y in the compound 1s

0.2 g of an organic compound contaning C, H and O on combustion gave 0.147 g of CO_(2) and 0.12 g of water . The percentage content of oxygen in the compound is :

1.2 g of an organic compound containing C, H and oxygen on combustion gave 2.64 g CO_2 and 1.08 g H_2 O . The mass of oxygen in 1.2 g of the compound is

0.290 g of an organic compound containing C, H and O gave on combustion 0.270 g of water and 0.66 g of CO_(2) . What is empirical formula of the compound.

44 g of a sample of organic compound on complet combustion gives 88 g CO_(2) and 36 g of H_(2)O . The molecular formula of the compound may be :-

0.36g of an organic compound on combustion gave 1.1g of CO_(2) and 0.54g of H_(2)O . The percentages of carbon and Hydrogen in the compound are

0.2g of an organic compound gave on combustion 0.55gm of CO_(2) and 0.0892g of H_(2)O .Calculate the percentage composition of Carbon in the compound.