For the following process, `H_(2)(g)rarr2H(g)`. It absorbs `438kJmol^(-1)` . Thus,

Predict the sign of Delta S for the following process : H_(2)O_((g)) rarr H_(2)O_((l))

Predict the sign of DeltaS for each of the following process: a. O_(2)(g) rarr 2O(g) b. N_(2)(g) +3H_(2)(g) rarr 2NH_(3)(g) c. C(s) +H_(2)O(l) rarr CO(g) +H_(2)(g) d. Br_(2)(l) rarr Br_(2)(g) e. N_(2)(g, 10 atm) rarr N_(2)(g,1atm) f. Desalination of water. g. Devitrification of glass h. Hard boiling og an egg i. C(s, "graphite") rarr C(s, "diamond")

Predict the sign of DeltaS for each of the following process: a. O_(2)(g) rarr 2O(g) b. N_(2)(g) +3H_(2)(g) rarr 2NH_(3)(g) c. C(s) +H_(2)O(l) rarr CO(g) +H_(2)(g) d. Br_(2)(l) rarr Br_(2)(g) e. N_(2)(g, 10 atm) rarr N_(2)(g,1atm) f. Desalination of water. g. Devitrification of glass h. Hard boiling of an egg i. C(s, "graphite") rarr C(s, "diamond")

The average O-H bond energy in H_(2)O with the help of following data. (1) H_(2)O(l)rarrH_(2)O(g), Delta H= +40.6 kJ mol^(-1) (2) 2H(g)rarrH_(2)(g), DeltaH= -435.kJ mol^(-1) (3) O_(2)(g)rarr2O(g), Delta H= +489.6 kJ mol^(-1) (4) 2H_(2)(g)+O_(2)(g)rarr2H_(2)O(l), Delta H= -571.6 kJ mol^(-1)

For the reaction N_(2)(G)+3H_(2)(g)hArr2NH_(3)(g),Delta=-93.6KJmol^(-1) The number of moles of H_(2) at equilibrium will increase If :

Calculate the standard enthalpy of formation of acetylena from the following data: C(s)+O_(2)(g)to CO_(2)(g), DeltaH^(@)=-393.5KJmol^(-1) H_(2)(g)+(1)/(2)O_(2)(g)to H_(2)O(l),DeltaH^(@)=-285 .8KJmol^(-1) 2C_(2)H_(2)(g)+50_(2)(g)to 4Co_(2)(g)+2H_(2)O(l0, DeltaH^(@)=-2598.8KJmol^(-1)

Calculate in kJ for the following reaction : C(g) + O_(2)(g) rarr CO_(2)(g) Given that, H_(2)O(g) + C(g) + H_(2)(g) , Delta H = +131 kJ CO(g) + 1/2 O_(2)(g) rarr CO_(2)(g), " " Delta H = -242 kJ H_(2)(g) + 1/2 O_(2)(g) rarr H_(2)O(g), " "DeltaH = -242 kJ

Calculate in kJ for the following reaction : C(g) + O_(2)(g) rarr CO_(2)(g) Given that, H_(2)O(g) + C(g) + H_(2)(g) , Delta H = +131 kJ CO(g) + 1/2 O_(2)(g) rarr CO_(2)(g), " " Delta H = -242 kJ H_(2)(g) + 1/2 O_(2)(g) rarr H_(2)O(g), " "DeltaH = -242 kJ