Consider the frequency distribution, where A is a positive interger :
`{:("x",A,2A,3A,4A,5A,6A),("f",2,1,1,1,1,1):}`

Consider the frequency distribution, where A is a positive interger : variance is 160. {:("x",A,2A,3A,4A,5A,6A),("f",2,1,1,1,1,1):} .

Consider the frequency distribution, where A is a positive interger : variance is 160. {:("x",A,2A,3A,4A,5A,6A),("f",2,1,1,1,1,1):} .

The frequency distribution for x is an given below. What is the range of f? {:(x,f),(0,1),(1,5),(2,4),(3,4):}

The frequency distribution is given below. {:(x,k,2k,3k,4k,5k,6k),(f,2,1,1,1,1,1):} In the table, k is a positive integer, has a varience of 160. Determine the value of k.

The frequency distribution is given below. {:(x,k,2k,3k,4k,5k,6k),(f,2,1,1,1,1,1):} In the table, k is a positive integer, has a varience of 160. Determine the value of k.

If the mean of the distribution is 2.6, then the value of y is {:("Variate x",1,2,3,4,5),("Frequency f of x",4,5,y,1,2):}

If the mean of the distribution is 2.6, then the value of y is {:("Variate x",1,2,3,4,5),("Frequency f of x",4,5,y,1,2):}

If the mean of the distribution is 2.6, then the value of y is {:("Variable x",1,2,3,4,5),("Frequency f of x",4,5,y,1,2):}

If the mean of the distribution is 2.6, then the value of y is {:("Variate x",1,2,3,4,5),("Frequency f of x",4,5,y,1,2):}

If the mean of the following distribution is 2.6., then y = . . . . {:(x_(i),1,2,3,4,5),(f_(t)"",4,5,y,1,2):}