A force `vecF=(5hati+3hatj)N` is applied over a particle which displaces it from its original position to the point `vecs=S(2hati-1hatj)m`. The work done on the particle is

A force vecF=(5hati+3hatj+2hatk)N is applied over a particle which displaces it from its origin to the point vecr=(2hati-hatj) m. The work done on the particle in joules is :

A force vecF=(5hati+3hatj) Newton is applied over a particle which displaces it from its origin to the point vecr=(2hati-1hatj) metres. The work done on the particle is

A force F = (5 hati + hatj) newtons is is applied over a partical which displaced it from its origin to the point r = (2 hati - hatj) metres . The work done on the partical is.

A force vecF =(5hati+3hatj+2hatk)N acts on a particle , and the particle moves from the origin to a point vecr=(2hati-hatj) m. what will be the work done on the particle ?

A constant force vecF=(3hati+2hatj+2hatk) N acts on a particle displacing it from a position vec(r_1)=(-hati+hatj-2hatk)m to a new position vecr_2=(hati-hatj+3hatk)m . Find the work done by the force.