[" (B) "I],[" r of the system of equations "3x+y+2z=3,2x-3y-z=-3,x+2],[" (B) "1,4,1],[" (C) "1,-2,-1]

The values of x,y,z in order of the system of equations 3x+y+2z=3,2x-3y-z=-3,x+2y+z=4, are (A)2,1,5(B)1,1,1(C)1,-2,-1(D)1,2,-1

The system of equations x +2y+3z=1, x-y+4z=0, 2x+y+7z=1 has

The solution of the system of equations is x-y+2z=1,2y-3z=1 and 3x-2y+4y=2 is

Use the product [(1,-1,2),(0,2,-3),(3,-2,4)][(-2,-0,1),(9,2,-3),(6,1,-2)] to solve the system of equations x - y + 2z = 1 2y - 3z = 1 3x - 2y + 4z = 2

Examine the consistency of the system of equations : 3x-y-2z=2, 2y-2z=-1, 3x-5y =3

Use product : {:[(1,-1,2),(0,2,-3),(3,-2,4)][(-2,0,1),(9,2,-3),(6,1,-2)] to solve the system of equations: x-y+2z=1,2y-3z=1,3x-2y+4z=2

Use product [[1,-1,2],[0,2,-3],[3,-2,4]][[-2,0,1],[9,2,-3],[6,1,-2]] to solve the system of equations x-y+2z = 1, 2y - 3z = 1, 3x-2y+4z = 2

The number of solutions of the system of equations: 2x+y-z=7,\ \ x-3y+2z=1,\ \ x+4y-3z=5 is (a) 3 (b) 2 (c) 1 (d) 0

The number of solutions of the system of equations: 2x+y-z=7x-3y+2z=1, is x+4y-3z=53(b)2 (c) 1 (d) 0