|10,int{1+tan x*tan(x+alpha)}dx=

Evaluate: int{1+tan x tan(x+theta)}dx

int[1+tanx.tan(x+alpha)]dx is equal to

int[1+tanx.tan(x+alpha)]dx is equal to

The value of int {1+tan x*tan (x + A)}\ dx is

The value of int {1+tan x*tan (x + A)}\ dx is

int(tan x-tan alpha)/(tan x+tan alpha)dx

int tan x tan 2x tan 3x dx

The value of int{1+tan x*tan(x+A)}backslash dx

Let alpha in (0, pi/2) be fixed. If the integral int(tan x + tan alpha)/(tan x - tan alpha)dx = A(x)cos 2 alpha+B(x) sin 2 alpha +C ,where C is a constant of integration, then the functions A(x) and B(x) are respectively.